Answer:
a) [tex]\frac{Ws}{Es} = \frac{200}{1+1.2s}[/tex]
b) attached below
c) type zero system
d) k > [tex]\frac{g}{200}[/tex]
e) The gain K increases above % error as the steady state speed increases
Explanation:
Given data:
Motor voltage = 12 v
steady state speed = 200 rad/s
time taken to reach 63.2% = 1.2 seconds
a) The transfer function of the motor from voltage to speed
let ; [tex]\frac{K1}{1+St}[/tex] be the transfer function of a motor
when i/p = 12v then steady state speed ( k1 ) = 200 rad/s , St ( time constant ) = 1.2 sec
hence the transfer function of the motor from voltage to speed
= [tex]\frac{Ws}{Es} = \frac{200}{1+1.2s}[/tex]
b) draw the block diagram of the system with plant controller and the feedback path
attached below is the remaining part of the detailed solution
c) The system is a type-zero system because the pole at the origin is zero
d) ) k > [tex]\frac{g}{200}[/tex]