Answer:
–1647.45 J
Explanation:
From the question given above, the following data were obtained:
Mass (M) = 112.5 g
Initial temperature (T₁) = 12.5 °C
Final temperature (T₂) = 9°C
Specific heat capacity (C) = 4.184 J/g°C
Heat (Q) absorbed =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial temperature (T₁) = 12.5 °C
Final temperature (T₂) = 9°C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 9 – 12.5
ΔT = –3.5 °C
Finally, we shall determine the heat absorbed. This can be obtained as follow:
Mass (M) = 112.5 g
Change in temperature (ΔT) = –3.5 °C
Specific heat capacity (C) = 4.184 J/g°C
Heat (Q) absorbed =?
Q = MCΔT
Q = 112.5 × 4.184 × –3.5
Q = –1647.45 J
