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The string at the right is 6.0 meters long and is vibrating as the third harmonic. The string vibrates up and down with 45 cycles in 10 seconds.
Determine the frequency, period, wavelength, and speed for this wave

Respuesta :

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Answer:

L = 6 m n = 3 f = 45/10 = 4.5 Hz → T = 1/f = 0.22 s

wavelength = 2L/n = 2×6÷3= 4 m

speed(v) = wavelength × f = 4×4.5 = 18 m/s

Explanation:

second solution for frequency:

f= speed(v) / wavelength = nv/2L = 3×18÷(2×6) = 4.5 Hz