Respuesta :
The given question is incomplete. The complete question is:
10 gram sample of methane [tex](CH_4)[/tex] has the same number of molecules as 10 gram sample of [tex]O_2[/tex]. True or False
Answer: Thus the statement is False.
Explanation:
According to avogadro's law, 1 mole of every substance contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar Mass}}[/tex]
1. [tex]\text{Number of moles for methane}=\frac{10g}{16g/mol}=0.625moles[/tex]
Now 1 mole of [tex]CH_4[/tex] molecule contains = [tex]6.023\times 10^{23}[/tex] of molecules
0.625 mole of [tex]CH_4[/tex] molecule contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.625=3.76\times 10^{23}[/tex] molecules
2. [tex]\text{Number of moles for oxygen}=\frac{10g}{32g/mol}=0.3125moles[/tex]
Now 1 mole of [tex]O_2[/tex] molecule contains = [tex]6.023\times 10^{23}[/tex] of molecules
0.3125 mole of [tex]O_2[/tex] molecule contains = [tex]\frac{6.023\times 10^{23}}{1}\times 0.3125=1.88\times 10^{23}[/tex] molecules
The number of molecules are different.
