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A 60 kg swimmer at a water park enters a pool using a 2 m high slide. Find the velocity of the swimmer
at the bottom of the slide.

Respuesta :

Answer:

the velocity of the swimmer at the bottom of the slide is 6.26 m/s

Explanation:

The computation of the velocity of the swimmer at the bottom of the slide is given below:

v = √2gh

= √2 × 9.8 × 2

= 6.26 m/s

Hence, the velocity of the swimmer at the bottom of the slide is 6.26 m/s

The velocity of the swimmer at the bottom of the slide will be 6.26 m/s.The pace of displacement change  with reference to time is referred to as the velocity

What is velocity?

The change of displacement with respect to time is defined as the velocity. Velocity is a vector quantity. it is a time-based component. Velocity at any angle is resolved to get its component of x and y-direction.

The velocity is found as;

[tex]\rm v= \sqrt{2gh} \\\\ \rm v= \sqrt{2\times 9.81 \times 2}\\\\ \rm v= 6.26 \ m/sec[/tex]

Hence velocity of the swimmer at the bottom of the slide will be 6.26 m/s.

To learn more about the velocity refer to the link ;

https://brainly.com/question/862972