Saline is a 0,154 M NaCl solution.
If the mass of NaCl is used to prepare saline solution was 45,045 grams, find the volume of solution that was obtained.
(Na:23; Cl:35,5)

Respuesta :

Answer: The volume of solution is 200 ml

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in ml

moles of [tex]NaCl[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{45.045g}{58.5g/mol}=0.77mol[/tex]

Now put all the given values in the formula of molality, we get

[tex]0.154=\frac{0.77\times 1000}{V_s}[/tex]

[tex]V_s=\frac{0.154\times 1000}{0.77}=200ml[/tex]

Therefore, the volume of solution is 200 ml