Answer: B. [tex]\frac{\text {2 mol} H_2O}{\text {2 mol HCl}}[/tex]
Explanation:
The balanced chemical equation is:
[tex]Ca(OH)_2(aq)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)[/tex]
is the limiting reagent as it limits the formation of product and is the excess reagent.
According to stoichiometry :
2 moles of produce = 2 moles of
Thus 3.25 moles of [tex]HCl[/tex] will produce=[tex]\frac{2}{2}\times 3.25=3.25moles[/tex] of [tex]H_2O[/tex]
Thus the tile used is [tex]\frac{\text {2 mol } H_2O}{\text {2 mol HCl}}[/tex]
