Work out the size of angle BCD
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Answer:
sin62=BD/AB
BD=Sin62×AB
BD=Sin62×15
BD=13.24
ALSO,
Tan C = BD/BC
Tan C = 13.24/24
Tan C = 5.51 / 10
C = Tan^-1 ( 5.51 / 10 )
Answer:
∠BCD = 29°
Step-by-step explanation:
sin 62 = BD/15
0.8829 = BD/15
BD = 13.24
tan ∠BCD = 13.24/24 = 0.5517
∠BCD = 29°