BD=16 and ÁT is the
perpendicular bisector of BD. Y=?
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Answer:
[tex]y= 5[/tex]
Step-by-step explanation:
Given
[tex]BD = 16[/tex]
[tex]BC = 2y - 2[/tex]
[tex]CD = y + 3[/tex]
Required
Find y
[tex]BD = BC + CD[/tex]
So, the expression becomes
[tex]16 = 2y - 2 + y + 3[/tex]
Collect like terms
[tex]16 = 2y + y- 2 + 3[/tex]
[tex]16 = 3y+1[/tex]
Collect like terms
[tex]3y = 16 - 1[/tex]
[tex]3y = 15[/tex]
Make y the subject
[tex]y= 15/3[/tex]
[tex]y= 5[/tex]