Answer:
0, 1 and 1
Step-by-step explanation:
Given the expressions;
x^3-2x^2+x = 0
x(x^2-2x+1) = 0
x = 0 and x^2-2x+1 = 0
Factorize x^2-2x+1 = 0
x^2-x-x+1 = 0
x(x-1)-1(x-1) = 0
(x-1)(x-1)= 0
x = 1 twice
hence the zeros of the equation are 0, 1 and 1
