Double and half angle identities?
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Answer:
Option 4
Step-by-step explanation:
Given:
Sinθ = [tex]\frac{15}{17}[/tex]
Since, cos2θ = 1 - 2sin²θ
cos2θ = [tex]1-2(\frac{15}{17})^2[/tex]
cos2θ = 1 - [tex]\frac{450}{289}[/tex]
cos2θ = [tex]\frac{289-450}{289}[/tex]
cos2θ = [tex]-\frac{161}{289}[/tex]
Therefore, Option 4 will be the answer.