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Sulfur hexafluoride, SF6, is a colorless, odorless, very unreactive gas. Calculate the pressure (in atm) exerted by 2.02 moles of the gas in a steel container of volume 6.21 L at 70 ℃.

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KyanLin

Answer:

9.15 atm

Explanation:

Ideal gas equation of state PV=nRT

P in hPa, V in L, n in mol, R is a constant which is 83.1 hpa*L/mol*k, T in kelvin.

Plug in all the number, and we will get:

P*6.21=2.02*83.1*343

P =9271.6(in hpa)=9.15 atm

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