contestada

The hydrogen ion concentration (h+) in a certain cleaning compound is (h+)=3.2x10^-11 use the formula ph=-log(h+) to find the pH of the clean compound the pH is approximately

Respuesta :

xero099

Answer:

The [tex]pH[/tex] of the clean compound is approximately 10.495.

Step-by-step explanation:

If the cleaning ion concentration of the cleaning compound is [tex][H^{+}] = 3.2\times 10^{-11}[/tex], then the [tex]pH[/tex], no unit, of the compound is:

[tex]pH = -\log_{10} [H^{+}][/tex]  (1)

[tex]pH = -\log_{10} (3.2\times 10^{-11})[/tex]

[tex]pH = -\log_{10} 3.2 - \log_{10} (10^{-11})[/tex]

[tex]pH = -\log_{10} \frac{32}{10} +11[/tex]

[tex]pH = -\log_{10} 32 + \log_{10} 10 + 11[/tex]

[tex]pH = -\log_{10} 32 +12[/tex]

[tex]pH \approx 10.495[/tex]

The [tex]pH[/tex] of the clean compound is approximately 10.495.