Answer:
1.06 atm
Explanation:
We are given the following variables to work with:
Initial pressure (P1): unknown
Initial temperature (T1): 348 K
Final temperature (T2): 506 K
Final pressure (P2): 1.55 atm
We are asked to find the initial pressure (P1). We want to choose a gas law equation that relates initial pressure and temperature to final pressure and temperature. Gay-Lussac's law does this:
[tex]\frac{P_{1}}{T_1} =\frac{P_{2}}{T_2} \\[/tex]
We can rearrange the law algebraically to solve for [tex]P_{1}[/tex].
[tex]{P_{1}} =\frac{(T_1)(P_{2} )}{T_2} \\[/tex]
Substitute your known variables and solve:
[tex]{P_{1}} =\frac{(348 K)(1.55 atm )}{506 K} \\ = 1.06 atm[/tex]
