The square pool was turned into a rectangular one and it's area was enlarged by a factor of 5 by enlarging one side of the pool by 3 meters and the other side by 14. What are the new dimensions of the pool?

[tex]5 {s}^{2} = (3 + s) \times (14 + s) \\ 5 {s}^{2} = {s}^{2} + 17s + 42 \\ {4s}^{2} - 17s - 42 = 0 \\ s = \frac{ - ( - 17) + \sqrt{ {( - 17)}^{2} - 4(4)(42)} }{2(4)} \\ s = \frac{17 + 31}{8} \\ s = 6 \\ hence \to \:the \: dimensions \: are : \\ b = s + 3 = 6 + 3 = 9 \: meters \\ l = s + 14 = 6 + 14 = 20 \: meters[/tex]

shivishivangi1679 shivishivangi1679 · Answer 2 · 2022-07-27T10:16:30+02:00

The new dimensions of the pool are; Width = 9 and Length = 20.

What is rectangular figure?

A rectangular prism is a three-dimensional shape that has two at the top and bottom and four are lateral faces.

It is given that the square pool was turned into a rectangular one and it's area was enlarged by a factor of 5 by enlarging one side of the pool by 3 meters and the other side by 14.

[tex]5s^2 = (3+s)(14 +s)\\\\5s^2 =s^2+ 17s + 42\\\\4s^2 - 17s - 42 = 0\\\\[/tex]

The root of the expression;

[tex]s = \dfrac{-(-17) + \sqrt{-17^2 - 4(4)(42)} }{2(4)} \\\\s = 6[/tex]

The dimensions are;

Width = 3 + s = 9

Length = 14 + s = 20

Learn more about the rectangle here;

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The square pool was turned into a rectangular one and it's area was enlarged by a factor of 5 by enlarging one side of the pool by 3 meters and the other side by 14. What are the new dimensions of the pool?​

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What is rectangular figure?

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The square pool was turned into a rectangular one and it's area was enlarged by a factor of 5 by enlarging one side of the pool by 3 meters and the other side by 14. What are the new dimensions of the pool?