Answer:
Let's choose the three odd consecutive numbers 1, 3, and 5.
3^2=9
1•5=5
9-5=4
Let's try the same thing, but with the numbers 101, 103, and 105.
103^2=10609
101•105=10605
10609-10605=4
So, yes, the square of the second number out of three consecutive odd numbers is four greater than the product of the first and the third numbers.
Pick 3 consecutive odd numbers:
3, 5, 7
Square the 2nd number: 5 ^ 2 = 25
Multiply the first and 3rd:
3 x 7 = 21
25-21 = 4
This is true.
Try another set of numbers:
9, 11, 13
11^2 = 121
9 x 13 = 117
121-117 = 4
Again it’s true.
