Given:
The limit problem is:
[tex]\lim_{x\to 3}(x^2+8x-2)[/tex]
To find:
The limit of the function by using direct substitution.
Solution:
We have,
[tex]\lim_{x\to 3}(x^2+8x-2)[/tex]
Applying limit, we get
[tex]\lim_{x\to 3}(x^2+8x-2)=(3)^2+8(3)-2[/tex]
[tex]\lim_{x\to 3}(x^2+8x-2)=9+24-2[/tex]
[tex]\lim_{x\to 3}(x^2+8x-2)=33-2[/tex]
[tex]\lim_{x\to 3}(x^2+8x-2)=31[/tex]
Therefore, the correct option is D.
