need help pls geometry question
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Answer:
55.94°
Step-by-step explanation:
Reference angle = x
Hyp = 25
Adjacent = 14
Apply CAH:
[tex] Cos(x) = \frac{Adj}{Hyp} [/tex]
[tex] Cos(x) = \frac{14}{25} [/tex]
[tex] x = Cos^{-1}(\frac{14}{25}) [/tex]
x = 55.9442023° ≈ 55.94° (to 2 d.p)