Answer: 126.1 grams of are needed to make 5.3 L of 0.25 M solution
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.
To calculate the mass of solute for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{given mass of solute}}{\text {Molar mass of solute}\times \text{Volume of solution in L}}[/tex]
[tex]0.25M=\frac{x}{95.2g/mol\times 5.3L}[/tex]
[tex]x=126.1g[/tex]
Thus 126.1 grams of are needed to make 5.3 L of 0.25 M solution
