Answer:
78.12 L
Explanation:
Given that,
Initial volume, V₁ = 105 L
Initial temperature, T₁ = 20°C = 20+273 = 293 K
New temperature, T₂ = -55 °C = 218 K
We need to find the new volume of the balloon. The relation between the volume and the temperature is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}[/tex]
Where
V₂ is the new volume
[tex]V_2=\dfrac{V_1T_2}{T_1}\\\\V_2=\dfrac{105\times 218}{293}\\\\V_2=78.12\ L[/tex]
So, the new volume is 78.12 L.
