How many moles of water are produced when 6.0 moles of hydrogen gas react with 2.5 moles of oxygen gas?

2.5 mole O2 should react (2 * 2.5) = 5.0 mole H2 but there is 6.0 mole H2. H2 remain in excess. O2 is the limiting reactant. mole of H2O formed = 2 * 2.5 = 5.0 mole.

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achulaksh achulaksh · Answer 2 · 2022-06-29T19:38:14+02:00

Moles of water are produced when 6.0 moles of hydrogen gas react with 2.5 moles of oxygen gas

Balanced equation: 2H2 + O2 → 2H2O

2.5 mole O2 should react (2 × 2.5) = 5.0 mole

H2 but there is 6.0 mole H2.

H2 remain in excess. O2 is the limiting reactant.

mole of H2O formed = 2 × 2.5 = 5.0 mole.

= 5.0 mole

If less than 6 moles of oxygen are available per mole of glucose, oxygen is the limiting reactant. The ratio is 6 mole oxygen per 1 mole glucose, OR 1 mole oxygen per 1/6 mole glucose.

Limiting reactant-

Limiting reactant- the reactant that determines the amount of product that can be produced because of the amount of that reactant present. Whichever reactant yields the LEAST amount of product is the limiting reactant. This will be completely used up in the reaction. After the reaction is complete, there will be product, and unused excess reactant.

Learn more about oxygen gas, refer

https://brainly.com/question/25800165

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