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A gas occupies 5.0 cubic meters at a temperature of 600. K. If the temperature is lowered to 300. K at constant pressure, the new volume occupied by the gas will be:

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sebassandin

Answer:

[tex]V_2=2.5m^3[/tex]

Explanation:

Hello!

In this case, according to the Charles' law as a directly proportional relationship between volume and temperature:

[tex]\frac{V_2}{T_2}=\frac{V_1}{T_1}[/tex]

Thus, in order to compute the final volume, V2, we obtain the following expression:

[tex]V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5m^3*300K}{600K}\\\\V_2=2.5m^3[/tex]

Best regards!

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