Complete Question:
The expression 16t² represents the distance in feet an object falls after t seconds. The object is dropped from a height of 906 feet. What is the height in feet of the object 2 seconds after it is dropped?
Answer:
H(2) = 842 feet
Step-by-step explanation:
Let the height be H.
Given the following data;
H(t) = 16t²
Height, H = 906 feet
Time, t = 2 seconds
To find the time, t at 2 seconds, we would use the following formula;
H(t) = H - 16t²
H(2) = 906 - 16(2)²
H(2) = 906 - 16*4
H(2) = 906 - 64
H(2) = 842 feet
Therefore, the height in feet of the object 2 seconds after it is dropped is 842.
