During the two hours of the morning rush from 8 a.m. to 10 a.m., 80 customers per hour arrive at the coffee shop. The coffee shop has a capacity of 60 customers per hour. On average how long does a customer arriving during the morning rush wait to be served

Respuesta :

Answer:

The average waiting time is 1/3 hours (or 20 minutes)

Step-by-step explanation:

Given

[tex]T = 2hours[/tex] --- Time

[tex]D = 80\ customers/hr[/tex] --- Arrivals

[tex]C = 60\ customers/hr[/tex] --- Capacity

Required

Determine the average waiting time

The average waiting time (AT) is calculated using the following formula:

[tex]AT = \frac{1}{2} * T * (\frac{D}{C} - 1)[/tex]

This gives:

[tex]AT = \frac{1}{2} * 2 * (\frac{80}{60} - 1)[/tex]

[tex]AT = 1*(\frac{80}{60} - 1)[/tex]

[tex]AT = (\frac{80}{60} - 1)[/tex]

Remove bracket

[tex]AT = \frac{80}{60} - 1[/tex]

Take LCM

[tex]AT = \frac{80-60}{60}[/tex]

[tex]AT = \frac{20}{60}[/tex]

[tex]AT = \frac{1}{3} hr[/tex]

or

[tex]AT = \frac{1}{3} * 60\ mins[/tex]

[tex]AT = 20\ mins[/tex]