Part (a)
Answers:
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Work Shown:
Refer to figure 1 in the screenshot attached below.
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Part (b)
Answers:
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Work Shown:
Refer to figure 2 in the screenshot attached below.
Correction:
The derivative for h should be
[tex]h(x) = f(x)*(x-1)^{-1}\\\\h'(x) = \frac{d}{dx}[f(x)*(x-1)^{-1}]\\\\h'(x) = \frac{d}{dx}[f(x)]*(x-1)^{-1}+f(x)*\frac{d}{dx}[(x-1)^{-1}]\\\\h'(x) = f'(x)*(x-1)^{-1}+f(x)*(-1(x-1)^{-2})\\\\[/tex]
I had a -2 in there instead of -1 as the coefficient.
You should find that h ' (2) = -2
That would then lead to y = -2x+9
The steps shown in figure 2 are effectively the same, just with different numbers of course.
