Which function is shown in the graph below?

On a coordinate plane, an exponential function shows decay. It rapidly decreases into quadrant 1 and approaches y = 1 in quadrant 1.
y = (one-half) Superscript x + 3 Baseline minus 1
y = (one-half) Superscript x minus 3 Baseline + 1
y = (one-half) Superscript x minus 1 Baseline + 3
y = (one-half) Superscript x + 1 Baseline minus 3

Which function is shown in the graph below On a coordinate plane an exponential function shows decay It rapidly decreases into quadrant 1 and approaches y 1 in class=

Respuesta :

Answer:

Option B, y = 2 Superscript x + 2 Baseline + 3

Step-by-step explanation:

I could be wrong tbh. I graphed it on a graphing website and the graph from B matched up with the graph shown in the question.

Hope this helps Bye =)

The exponential function is given by [tex]y=(\frac{1}{2})^{x-3} +1[/tex]

Exponential function

An exponential function is in the form:

y = abˣ

Where y,x are variables, a is the initial value of y and b is the multiplication factor.

The exponential function is given by [tex]y=(\frac{1}{2})^{x-3} +1[/tex]

From the point (0, 9):

[tex]y=(\frac{1}{2})^{0-3} +1=9[/tex]

Also at point (3, 2):

[tex]y=(\frac{1}{2})^{3-3} +1=2[/tex]

Find out more on Exponential function at: https://brainly.com/question/12940982