Answer:
2 - 30ft²
3 - 57yd²
Step-by-step explanation:
Hey There!
The first step in solving this problem is finding the formula for area of a trapezoid
[tex]A = \frac{a+b}{2} h[/tex]
a = base 1
b = base 2
h = height
For the first one the dimensions are
a = 6
b = 9
h = 4
now we just plug in the values
[tex]A=\frac{6+9}{2} 4\\6+9=15\\\frac{15}{2}=7.5\\7.5*4=30[/tex]
so the area of the first trapezoid is 30 ft²
For the second one the given dimensions are
a = 8
b = 11
h = 6
now we just plug in the values
[tex]A=\frac{8+11}{2} 6\\8+11=19\\\frac{19}{2} =9.5\\9.5*6=57[/tex]
so the area of the second trapezoid is 57 yd²
