Answer:
See Explanation
Step-by-step explanation:
The question is incomplete. However, I will solve using the following assumptions.
Job A:
[tex]y = 2x + 5[/tex]
Job B
[tex]\begin{array}{cccccc}x & {1} & {2} & {3} & {4} & {5} \ \\ y & {6} & {10} & {14} & {18} & {22} \ \end{array}[/tex]
The first step is to calculate the rate of Job B using:
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Where:
[tex](x_1,y_1) = (1,6)[/tex]
[tex](x_2,y_2) = (2,10)[/tex]
So, we have:
[tex]m = \frac{10 - 6}{2 - 1}[/tex]
[tex]m = \frac{4}{1}[/tex]
[tex]m = 4[/tex]
So, the hourly rate of job B is $4/hr
For Job A:
[tex]y = 2x + 5[/tex]
A linear equation has the form:
[tex]y = mx + b[/tex]
Where m is the rate
By comparison:
[tex]m = 2[/tex]
So, the hourly rate of Job A is $2/hr
Comparing both rates, we can draw the following conclusions;