Respuesta :
n = first integer
n + 1 = second integer
n + 2 = third
n + 3 = fourth
the sum is 114 so:
n + (n + 1) + (n + 2) + (n + 3) = 114
solve:
4n + 6 = 114
4n = 108
n = 27
so 27 is your first.
27 + 1 is your second (remember n +1 n +2 and n +3)
so your first four integers are: 27 28 29 and 30
(I'll also help with one)
week one: x
week two: x + 5
week three: 2(x+5) or 2x + 10
week1 + 2 + 3 = 431
so its:
x + (x+5) + (2x + 10)
4x + 15 = 431
4x = 416
x = 104
its then:
week one: 104 sold
week two: 109 sold (x + 5)
week three: 218 (2x + 10)
n + 1 = second integer
n + 2 = third
n + 3 = fourth
the sum is 114 so:
n + (n + 1) + (n + 2) + (n + 3) = 114
solve:
4n + 6 = 114
4n = 108
n = 27
so 27 is your first.
27 + 1 is your second (remember n +1 n +2 and n +3)
so your first four integers are: 27 28 29 and 30
(I'll also help with one)
week one: x
week two: x + 5
week three: 2(x+5) or 2x + 10
week1 + 2 + 3 = 431
so its:
x + (x+5) + (2x + 10)
4x + 15 = 431
4x = 416
x = 104
its then:
week one: 104 sold
week two: 109 sold (x + 5)
week three: 218 (2x + 10)