Answer:
Lower limit: 49.44 minutes
Upper limit: 53.16 minutes
Step-by-step explanation:
T interval
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 40 - 1 = 39
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 39 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.023
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.023\frac{5.8}{\sqrt{40}} = 1.86[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 51.3 - 1.86 = 49.44 minutes
The upper end of the interval is the sample mean added to M. So it is 51.3 + 1.86 = 53.16 minutes
Lower limit: 49.44 minutes
Upper limit: 53.16 minutes