Answer:
b
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
[tex]\frac{KL}{EF}[/tex] = [tex]\frac{JK}{DE}[/tex] , substitute values
[tex]\frac{6x+3}{x+11}[/tex] = [tex]\frac{25}{10}[/tex] ( cross- multiply )
10(6x + 3) = 25(x + 11) ← distribute parenthesis on both sides
60x + 30 = 25x + 275 ( subtract 25x from both sides )
35x + 30 = 275 ( subtract 30 from both sides )
35x = 245 ( divide both sides by 35 )
x = 7
Then
KL = 6x + 3 = 6(7) + 3 = 42 + 3 = 45 → b
