Hi there! Your answe is 24c
Please see an explanation below for a clear understanding to your problem.
Any questions about my explanation and answer can be asked through comments! :)
Step-by-step explanation:
[tex] \large \boxed{ {x}^{2} - {y}^{2} = (x + y)( x - y)}[/tex]
The formula above is what we will be using. This is called "Difference of Two Squares".
Notice how the these expressions are similar to the formula's structure.
[tex] \large{ {(3c + 2)}^{2} - {(3c - 2)}^{2} }[/tex]
Notice how there are minus sign, squared expression which we can factor by using the formula above. Therefore -
[tex] \large{ {x}^{2} = {(3c + 2)}^{2} } \\ \large{x = 3c + 2}[/tex]
Therefore, our y would be 3c-2.
Then proceed with the formula.
[tex] \large{ {(3c + 2)}^{2} - {(3c - 2)}^{2} = (3c + 2 + 3c - 2)(3c + 2 - (3c - 2))}[/tex]
Simplify.
[tex] \large{ (6c)(3c + 2 - 3c + 2)} \\ 6c(4) \\ 24c[/tex]
