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A store sells 8 colors of balloons with at least 28 of each color. How many different combinations of 28 balloons can be chosen? Apply the method of Example 9.6.2 using balloons instead of cans of soft drinks to find that the number of different combinations of 28 balloons that can be chosen is . (b) If the store has only 12 red balloons but at least 28 of each other color of balloon, how many combinations of balloons can be chosen? Use the method of Example 9.6.2(c) to answer this question. If the store has only 12 red balloons, then the number of different selections of 28 balloons of the different colors is the same as the number of different selections that contain 12 or fewer red balloons. Let T be the set of all possible selections, assuming that there are at least 28 balloons of each type, let R≤12 be the set of selections in T that contain 12 or fewer red balloons, and let R≥13 be the set of selections from T that contain 13 or more red balloons. Use the relationships among R≤12, R≥13, and T to find that the number of different combinations of 28 balloons that can be chosen is . (c) If the store has only 8 blue balloons but at least 28 of each other color of balloon, how many combinations of balloons can be chosen? (d) If the store has only 12 red balloons and only 8 blue balloons but at least 28 of each other color of balloon, how many combinations of balloons can be chosen?

Respuesta :

MrRoyal

Answer:

(a) [tex]Selection = 6724520[/tex]

(b) [tex]At\ most\ 12 = 6553976[/tex]

(c) [tex]At\ most\ 8 = 6066720[/tex]

(d) [tex]At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638[/tex]

Step-by-step explanation:

Given

[tex]Colors = 8[/tex]

[tex]Balloons = 28[/tex] --- at least

Solving (a): 28 combinations

From the question, we understand that; a combination of 28 is to be selected. Because the order is not important, we make use of combination.

Also, because repetition is allowed; different balloons of the same kind can be selected over and over again.

So:

[tex]n => 28 + 8-1[/tex][tex]= 35[/tex]

[tex]r = 28[/tex]

[tex]Selection = ^{35}^C_{28[/tex]

[tex]Selection = \frac{35!}{(35 - 28)!28!}[/tex]

[tex]Selection = \frac{35!}{7!28!}[/tex]

[tex]Selection = \frac{35*34*33*32*31*30*29*28!}{7!28!}[/tex]

[tex]Selection = \frac{35*34*33*32*31*30*29}{7!}[/tex]

[tex]Selection = \frac{35*34*33*32*31*30*29}{7*6*5*4*3*2*1}[/tex]

[tex]Selection = \frac{33891580800}{5040}[/tex]

[tex]Selection = 6724520[/tex]

Solving (b): At most 12 red balloons

First, we calculate the ways of selecting at least 13 balloons

Out of the 28 balloons, there are 15 balloons remaining (i.e. 28 - 13)

So:

[tex]n => 15 + 8 -1 = 22[/tex]

[tex]r = 15[/tex]

Selection of at least 13 =

[tex]At\ least\ 13 = ^{22}C_{15}[/tex]

[tex]At\ least\ 13 = \frac{22!}{(22-15)!15!}[/tex]

[tex]At\ least\ 13 = \frac{22!}{7!15!}[/tex]

[tex]At\ least\ 13 = 170544[/tex]

Ways of selecting at most 12  =

[tex]At\ most\ 12 = Total - At\ least\ 13[/tex] --- Complement rule

[tex]At\ most\ 12 = 6724520- 170544[/tex]

[tex]At\ most\ 12 = 6553976[/tex]

Solving (c): At most 8 blue balloons

First, we calculate the ways of selecting at least 9 balloons

Out of the 28 balloons, there are 19 balloons remaining (i.e. 28 - 9)

So:

[tex]n => 19+ 8 -1 = 26[/tex]

[tex]r = 19[/tex]

Selection of at least 9 =

[tex]At\ least\ 9 = ^{26}C_{19}[/tex]

[tex]At\ least\ 9 = \frac{26!}{(26-19)!19!}[/tex]

[tex]At\ least\ 9 = \frac{26!}{7!19!}[/tex]

[tex]At\ least\ 9 = 657800[/tex]

Ways of selecting at most 8  =

[tex]At\ most\ 8 = Total - At\ least\ 9[/tex] --- Complement rule

[tex]At\ most\ 8 = 6724520- 657800[/tex]

[tex]At\ most\ 8 = 6066720[/tex]

Solving (d): 12 red and 8 blue balloons

First, we calculate the ways for selecting 13 red balloons and 9 blue balloons

Out of the 28 balloons, there are 6 balloons remaining (i.e. 28 - 13 - 9)

So:

[tex]n =6+6-1 = 11[/tex]

[tex]r = 6[/tex]

Selection =

[tex]^{11}C_6 = \frac{11!}{(11-6)!6!}[/tex]

[tex]^{11}C_6 = \frac{11!}{5!6!}[/tex]

[tex]^{11}C_6 = 462[/tex]

Using inclusion/exclusion rule of two sets:

[tex]Selection = At\ most\ 12 + At\ most\ 8 - (12\ red\ and\ 8\ blue)[/tex]

[tex]Only\ 12\ red\ and\ only\ 8\ blue\ = 170544+ 657800- 462[/tex]

[tex]Only\ 12\ red\ and\ only\ 8\ blue\ = 827882[/tex]

[tex]At\ most\ 12\ red\ and\ at\ most\ 8\ blue = Total - Only\ 12\ red\ and\ only\ 8\ blue[/tex]

[tex]At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 6724520 - 827882[/tex]

[tex]At\ most\ 12\ red\ and\ at\ most\ 8\ blue = 5896638[/tex]

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