Answer:
3224 kJ/mol
Explanation:
The combustion of benzoic acid occurs as follows:
C₇H₆O₂ + 13/2O₂ → 7CO₂ + 3H₂O + dE
The change in temperature in the reaction is the change due the energy released, that is:
3.256K * (10.134kJ / K) = 33.00kJ are released when 1.250g reacts
To find the heat released per mole we have to find the moles of benzoic acid:
Moles benzoic acid -Molar mass: 122.12g/mol-:
1.250g * (1mol / 122.12g) = 0.0102 moles
The dE combustion per mole of benzoic acid is:
33.00kJ / 0.0102moles =
3224 kJ/mol