Answer:
the probability the emergency cooling system will work when needed is 80.5%
Step-by-step explanation:
Given the data in the question;
the probability that someone will actually push the emergency button in an emergency from 90% to 99% of the time
E[tex]_4[/tex] ⇒ Someone will actually push the emergency button in an emergency
P(E[tex]_4[/tex]) = 90% = 0.90
E[tex]_4[/tex] : Someone will actually push the emergency button in an emergency
P(E[tex]_4[/tex]) = 99% = 0.99
P(E) = P(E1) × P(E2) × P(E3) × P(E4) × P(E5)
we substitute
P(E) = 92% × 94% × 96% 99% × 98%
P(E) = 0.8054
P(E) = 80.5%
Therefore, the probability the emergency cooling system will work when needed is 80.5%