Solve the radical equation.
x + 1 = sqrt -6x - 6
Which solution is extraneous?

a. The solution x=-1 is an extraneous solution.
b. Both x=-1 are x=-7 true solutions.
c. The solution x=-7 is an extraneous solution.
d. Neither x=-1 nor x=-7 is a true solution to the equation.

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Answer:

x -1 = Sqrt6

Step-by-step explanation:

D.) Is the Proper Answer

The solution x=-1 is an extraneous solution.

What is the radical equation?

Radical equations (also known as irrational) are equations in which the unknown value appears under a radical sign.

The given equation is;

[tex]\rm x+1=\sqrt{-6x-6}[/tex]

The solution of the equation is determined in the following steps given below.

Squaring on both the sides

[tex]\rm x+1=\sqrt{-6x-6}\\\\(x+1)^2=-6x-6\\\\x^2+2x+1=-6x-6\\\\x^2+2x+1+6x+6=0\\\\x^2+8x+7=0\\\\x^2+7x+x+7=0\\\\x(x+7)+1(x+7)=0\\\\(x+7)(x+1)=0\\\\x+7=0, \ x=-7\\\\x+1=0, \ x=-1[/tex]

Hence, the solution x=-1 is an extraneous solution.

Learn more abour radical expression here;

https://brainly.com/question/2292715

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