You park your car, and start walking west on Robinson Street at a speed of 2.1 m/s. After 16 minutes, you turn left. It really is a beautiful day out, and so you slow your speed to 1.1 m/s and continue walking to the south on Rosalind Avenue for another 12 minutes. At this point, you realize that you have a library book on hold at the downtown branch, and decide to make a quick detour to pick it up. You turn right and jog west at a speed of 3.4 m/s for 28 seconds to cross the street before the light changes. At this point, how far (in meters) are you from your car?

Respuesta :

Answer:

The distance is 2077.77m

Step-by-step explanation:

Given

Represent speed with s and time with t

[tex](s_1, t_1) = (2.1m/s,16min)[/tex] ---- Left

[tex](s_2, t_2) = (1.1m/s,12min)[/tex] --- South

[tex](s_3, t_3) = (3.4m/s,28sec)[/tex] ---- Right

Required

How far are you from your car?

[tex]distance=speed * time[/tex]

To solve this question, I will use the attached image to illustrate the movement.

First, we calculate distance AB

Using: [tex](s_1, t_1) = (2.1m/s,16min)[/tex] ---- Left

[tex]d_1 = s_1 * t_1[/tex]

[tex]d_1 = 2.1m/s * 16min[/tex]

Convert min to secs

[tex]d_1 = 2.1m/s * 16*60s[/tex]

[tex]d_1 = 2016m[/tex]

[tex]AB = 2016m[/tex]

Next, we calculate the distance BC

Using: [tex](s_2, t_2) = (1.1m/s,12min)[/tex] --- South

[tex]d_2 = 1.1m/s * 12min[/tex]

[tex]d_2 = 1.1m/s * 12*60s[/tex]

[tex]d_2 = 792m[/tex]

[tex]BC = 792m[/tex]

Next, we calculate distance CD

Using: [tex](s_3, t_3) = (3.4m/s,28sec)[/tex] ---- Right

[tex]d_3 = 3.4m/s * 28s[/tex]

[tex]d_3 = 95.2m[/tex]

[tex]CD = 95.2m[/tex]

The distance between you and the car is represented as AD.

Considering triangle AOD, we have:

[tex]AD^2 = AO^2 + OD^2[/tex]

Where:

[tex]AO = AB - BO[/tex]

and

[tex]BO = CD[/tex]

So:

[tex]AO = AB - CD = 2016m - 95.2m[/tex]

[tex]AO = 1920.8m[/tex]

[tex]OD = BC[/tex]

[tex]OD = 792m[/tex]

The equation becomes:

[tex]AD^2 = AO^2 + OD^2[/tex]

[tex]AD^2 = 1920.9^2 + 792^2[/tex]

[tex]AD^2 = 4317120.81m^2[/tex]

[tex]AD= \sqrt{4317120.81m^2[/tex]

[tex]AD= 2077.76822817 m[/tex]

[tex]AD= 2077.77 m[/tex] --- approximated