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The student is now told that the four solids, in no particular order, are barium chloride (BaCl2), sugar (C6H12O6), benzoic acid (C6H5COOH), and potassium bromide (KBr). Assuming that conductivity is correlated to the number of ions in solution, rank the four substances based on how well a 0.20 M solution in water will conduct electricity. Rank from most conductive to least conductive. To rank items as equivalent, overlap them.

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Answer:

-BaCl₂.

-KBr.

-C₆H₅COOH.

-C₆H₁₂O₆.

Explanation:

As the problem states, conductivity is related to the number of ions in solution, the larger the number of ions, the greater the conductivity.

Meaning the ranking from most conductive to least conductive is:

  • BaCl₂. It completely dissolves into three ions, one Ba⁺² and two Cl.
  • KBr. It completely dissolves into two ions, one K⁺ and one Br.
  • C₆H₅COOH. It partially dissolves into two ions, C₆H₅COO⁻ and H⁺.
  • C₆H₁₂O₆. It does not dissolve into ions.

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