Answer:
F = 8.48 x [tex]10^{-18}[/tex] N
Step-by-step explanation:
The force on an electron in a magnetic field can be determined by;
F = qvB Sin θ
where: e is the electron, v is its velocity, B is the measure of the magnetic field, and θ is the angle of its path.
Thus,
q = -1.6 x [tex]10^{-19}[/tex] C
v = 106 m/s
B = 0.5 T
θ = [tex]90^{o}[/tex]
So that,
F = 1.6 x [tex]10^{-19}[/tex] x 106 x 0.5
= 8.48 x [tex]10^{-18}[/tex] N
The force on the electron crossing the uniform magnetic field is 8.48 x [tex]10^{-18}[/tex] N.
