Answer: 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of calcium chloride
Explanation:
The balanced chemical equation is:
[tex]2Na_3PO_4+3CaCl_2\rightarrow 6NaCl+Ca_3(PO_4)_2[/tex]
According to stoichiometry :
2 moles of [tex]Na_3PO_4[/tex] require 3 moles of [tex]CaCl_2[/tex]
Thus both are limiting reagent as both will limit the formation of product.
As 2 moles of [tex]Na_3PO_4[/tex] reacts with 3 moles of [tex]CaCl_2[/tex] give = 6 moles of [tex]NaCl[/tex]
Thus 6 moles of NaCl are produced when 2 moles of sodium phosphate reacts with 3 moles of calcium chloride
