Given:
The equation is:
[tex]2-\dfrac{5}{6}x=\dfrac{7}{8}[/tex]
To find:
The simplified for of the given equation so that it does have fractions.
Solution:
We have,
[tex]2-\dfrac{5}{6}x=\dfrac{7}{8}[/tex]
Denominators values are 6 and 8. LCM of 6 and 8 is 24 so multiply both sides by 24.
[tex]24\left(2-\dfrac{5}{6}x\right)=24\times \dfrac{7}{8}[/tex]
[tex]24(2)-24\left(\dfrac{5}{6}x\right)=24\times \dfrac{7}{8}[/tex]
[tex]48-4\times 5x=3\times 7[/tex]
[tex]48-20x=21[/tex]
Therefore, the required equation is [tex]48-20x=21[/tex].
