Answer:
F' = 9F
Explanation:
The complete question is "Objects 1 and 2 attract each other with a electrostatic force of 36.0 units. If the charge of Object 2 is tripled, then the new electrostatic force will be _____ units".
The electric force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
If F = 36 units,
[tex]36=\dfrac{kq_1q_2}{r^2}\ ...(1)[/tex]
If charges are tripled, q₁' = q₂' = 3q₁ and 3q₂
So,
[tex]F'=\dfrac{kq_1'q_2'}{r^2}\\\\F'=\dfrac{k\times 3q_1'\times 3q_2'}{r^2}\\\\F'=9\times \dfrac{kq_1'q_2'}{r^2}\\\\F'=9F[/tex]
So, the new force becomes 9 times of the initial force.
