Answer: 10. 39.7 g [tex]CH_3OH[/tex]
11. 650 g of [tex]HgO[/tex]
Explanation:
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]
a) moles of [tex]H_2[/tex]
[tex]\text{Number of moles}=\frac{5.0g}{2.0g/mol}=2.5moles[/tex]
[tex]CO(g)+2H_2(g)\rightarrow CH_3OH(l)[/tex]
According to stoichiometry :
2 moles of [tex]H_2[/tex] produce = 1 mole of [tex]CH_3OH[/tex]
Thus 2.5 moles of [tex]H_2[/tex] produce=[tex]\frac{1}{2}\times 2.5=1.25moles[/tex] of [tex]CH_3OH[/tex]
Mass of [tex]CH_3OH=moles\times {\text {Molar mass}}=1.25moles\times 32g/mol=39.7g[/tex]
Thus 39.7 g of [tex]CH_3OH[/tex] will be produced from 5.0 g of hydrogen.
11. [tex]2HgO(s)\rightarrow 2Hg(l)+O_2(g)[/tex]
According to stoichiometry :
1 mole of [tex]O_2[/tex] is produced by = 2 moles of [tex]HgO[/tex]
Thus 1.50 moles of [tex]O_2[/tex] are produced by =[tex]\frac{2}{1}\times 1.50=3moles[/tex] of [tex]HgO[/tex]
Mass of [tex]HgO=moles\times {\text {Molar mass}}=3moles\times 216g/mol=650g[/tex]
Thus 650 g of [tex]HgO[/tex] woukd be decomposed to produce 1.5 mol of oxygen
