Answer:
[tex]h'(x) = -x + 5[/tex]
Step-by-step explanation:
Given
[tex]h(x) = -x+ 5[/tex]
Required
Determine the inverse
[tex]h(x) = -x+ 5[/tex]
Replace h(x) with y
[tex]y = -x+ 5[/tex]
Swap positions of x and y
[tex]x = -y+ 5[/tex]
Make y the subject
[tex]y = -x + 5[/tex]
Replace y with h'(x)
[tex]h'(x) = -x + 5[/tex]