Answer:
0.0474 atm
Explanation:
Hello!
In this case, since the pressure inside the balloon is greater than that of the troposphere, the positive pressure difference is given by:
[tex]\Delta P=100.4kPa-95.6\\\\\Delta P=4.8kPa[/tex]
Now, since 101.325 kPa = 1 atm, the pressure in atm would be:
[tex]4.8kPa*\frac{1atm}{101.325kPa}\\\\=0.0474atm[/tex]
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