A tennis ball, 0.314 kg, is accelerated at a rate of 164 m/s2 when hit by a professional tennis player. What force does the player's tennis racket exert on the ball?

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15-11-2016
Physics

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A tennis ball, 0.314 kg, is accelerated at a rate of 164 m/s2 when hit by a professional tennis player. What force does the player's tennis racket exert on the ball?

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AL2006 AL2006 · Answer 1 · 2016-11-15T06:48:30+01:00

Newton's 2nd law of motion:

Force = (mass) x (acceleration)

   = (0.314 kg) x (164 m/s²)

   = 51.5 newtons

   (about 11.6 pounds) .

Notice that the ball is only accelerating while it's in contact with the racket.
The instant the ball loses contact with the racket, it stops accelerating, and
sails off in a straight line at whatever speed it had when it left the strings.

ap8997154 ap8997154 · Answer 2 · 2022-01-28T08:25:03+01:00

To solve the problem we must know about Newton's law of motion.

What is Force?

According to Newton's Second law of motion, the force is the product of the mass of the object and the acceleration of the object.

Force = mass x acceleration

What is Newton's Third law of motion?

when two bodies interact then the force applied by them on each other is equal in magnitude and opposite in direction.

The force exerted by the player's tennis racket on the ball is 51.496 N.

Given to us

Mass of the tennis ball = 0.314 kg
Acceleration of the tennis ball = 164 m/sec²

Newton's Third law of motion,

Using Newton's Third law of motion, we can siy that the force exerted by the player's tennis racket is equal to the force by which the ball travels (or the force applied by the ball on the tennis racket).

Force exerted by the player's tennis racket on the ball

= Force by which the ball travels

Force by the player's tennis racket

We know that forcer is given as the product of mass and acceleration,

Force exerted by the player's tennis racket on the ball

= mass of the tennis ball x acceleration of the ball

= 0.314 x 164

= 51.496 N

Hence, the force applied by the tennis player on the ball is 51.496 N.

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