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A marble is thrown horizontally with a speed of 15.0 m/s from the top of a building. When it strikes the ground, the marble has a velocity that makes an angle of 65.0° with the horizontal. From what height above the ground the marble was thrown. How far from the base of the building, did the marble land?

Respuesta :

The answer is 52.79 m.

I used this formula to get the formula for Vy:
v^2=vi^2+2(a)(x)
And got
Vy=square root (19.6 h)

Then I used that and put it in this formula:

tan(65) =Vy/Vx

tan(65) = square root (19.6 h)/15.0

Then I rearranged it to:

h=[(15.0)(tan65)]/19.6

h=52.79 m
The answer for this question is 52.79

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