Answer:
Option e is correct.
Explanation:
An object of mass m moves horizontally, increasing in speed from 0 to v in a time t.
We know that,
Work done = change in kinetic energy
[tex]W=\dfrac{1}{2}m(v^2-u^2)[/tex]
Here, u = 0
So,
[tex]W=\dfrac{1}{2}mv^2[/tex]
Also,
Power = work done/time
So,
[tex]P=\dfrac{\dfrac{1}{2}mv^2}{t}\\\\=\dfrac{mv^2}{2t}[/tex]
So, the correct option is (e).