Answer:
0.1 m/s
Explanation:
Please see attached photo for explanation.
Mass of 1st cart (m₁) = 500 g
Initial velocity of 1st cart (u₁) = 0.25 m/s
Mass of 2nd cart (m₂) = 750 g
Initial velocity of 2nd cart (u₂) = 0 m/s
Velocity (v) after collision =.?
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(500 × 0.25) + (750 × 0) = v(500 + 750)
125 + 0 = v(1250)
125 = 1250v
Divide both side by 1250
v = 125 / 1250
v = 0.1 m/s
Thus, the two cart will move with a velocity of 0.1 m/s after collision.
The velocity of the cart will be 0.1 m/sec.Velocity is the rate of change of displacement. Its unit is m/sec.
According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
The given data in the problem is;
(m₁) is the mass of cart 1 = 500 g
(u₁) is the initial velocity of cart 1= 0.25 m/s
(m₂) is the mass of 2nd cart = 750 g
(u₂) is the initial velocity of 2nd cart = 0 m/s
(v) is the velocity after collision =.?
According to the law of conservation of momentum;
Momentum before collision =Momentum after collision
[tex]\rm m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\(500 \times 0.25) + (750 \times 0) = v \times (500 + 750) \\\\ 125 + 0 = v \times (1250) \times 125 \\\\ \rm v= \frac{125}{1250} \\\\ \rm v== 0.1 m/sec[/tex]
Hence the velocity of the cart will be 0.1 m/sec.
To learn more about the law of conservation of momentum refer;
https://brainly.com/question/1113396
