Respuesta :

Answer:

This is a tricky problem, don't feel bad for not knowing this  :/  I think this is too much in one question even :P  I'll give you the answers and how to get them but really it's going to be a lot to understand in one try.  Pay attention :P

Step-by-step explanation:

first graph the given table .. I use Desmos b/c it's handy

we want y = A[tex]x^{2}[/tex] + bx + c

given   1st      2nd

5          -5          2

0         -3           2

-3        -1           2

-4        1           2

-3        3          2

0         5          2

5          7        

12        

A=2nd / 2  = 2/2 = 1

B=?

C= 5

x=1

y=12

y = a[tex]x^{2}[/tex] + bx +c

12=[tex]1^{2}[/tex] + b(1) +5

12=1+ b +5

6=b   :)

y = [tex]x^{2}[/tex] + 6x +5       ( the answer to a) in the question )  

factor it

(x+5)(x+1)   ( answer to b) in the question

vertex form

y = a(x-h)2 + k

where  h = −b/2a

and k = f( h )

h=6/2(1) = 3

k = [tex]3^{2}[/tex] + 6(3) +5

k=32

y =x-3 + 32  ( answer to c)   in question )

let me know if this worked for you  :)  ( I did this fast late at night :/ )